Number dissected

55

Parous rate

65.5

Probability of survival (p)^{1}

0.87

P^{10} (%)

25

p^{10}/log_{e} p (days)^{2}

7.2

Vectorial capacity ^{3}

1.94

 ^{1}Thus the daily probability of survival (p) was taken as ^{3}√P (P = percentage parous)[45].
 p^{10} percentage of population expected to live long enough to become infective with an extrinsic cycle of 10 days for P. knowlesi.
 ^{2}life expectancy[46].
 ^{3}vectorial capacity VC = ma^{2}p^{n}/log^{e}p[47].